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一张数据表,存在重复数据.sElECt ID,NAmE,COUNT(...

select ID, count(Name) from A group by ID having count(Name) > 1

1、查出表中重复列的数据:select a,count(*) from table group by a having count(*)>1 2、查重复次数最多的列:select a,num from (select a,count(*) num from table group by a having count(*)>1)order by num desc 此外,还有 1、查询一个...

--假设表名为sales (销售) --,含有字段product (产品) ; select product , count(*) from sales group by product ; --如果还有流水号id,可以: select product , count(*) --不去重 , count(distinct id) --去重 from sales group by product ;

不会是id都相同吧 select A from 表 group by A having count(A)>1 1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断 select * from people where peopleId in (select peopleId from people group by peopleId having cou...

友善的提醒两点,如有帮助还望采纳,谢谢! 第一、你这个语句本身写的有点麻烦,简化如下 SELECT [Store_Abbreviation] ,[Goodname], [Goodmodel] ,SUM(Order_Quantity) AS Order_Quantity, [Workid]from [fangtaidata].[dbo].[SalesStatistics]...

select name,count(1)from tabnamegroup by namehaving count(1) > 1

试试下面的语句: delete 表 where (select count(1) from 表 as a where a.filename=表.filename and a.filetime>=表.filetime)>3

如果只是要图2的效果,排序就可以了 select * from table order by name;如果要查每个相同的名字分别有多少个 select name,count(*) from table group by name;

selectid,name,memo fromA whereidin(selectidfromAgroupbyidhavingcount(1)>=2) 1查询 abcd相同的记录: select * from F where a=b and b=c and c=d 2查询有重复数据的记录 select * from F group by a,b,c,d having count(*)>1 3取出数据过滤...

方法有很多,这里介绍两种 方法一、如果要保留id的最小值,例如: 数据:执行sql:select count(*) as count ,name,id from ceshi group by name<img 最后要删除的sql为:delete from ceshi where id not in (select count(*) as count ,n...

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