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一张数据表,存在重复数据.sElECt ID,NAmE,COUNT(...

select ID, count(Name) from A group by ID having count(Name) > 1

select a,count(*) from table group by a having count(*)>1 嗯。是的。这样是查出来该字段重复2次以上的列。

--假设表名为sales (销售) --,含有字段product (产品) ; select product , count(*) from sales group by product ; --如果还有流水号id,可以: select product , count(*) --不去重 , count(distinct id) --去重 from sales group by product ;

select id, name, memo from A where id in (select id from A group by id having count(1) >= 2)

select name,count(1)from tabnamegroup by namehaving count(1) > 1

DELETE FROM table_name a WHERE rowid > ( SELECT min(rowid) FROM table_name b WHERE b.id = a.id and b.name=a.name);

不会是id都相同吧 select A from 表 group by A having count(A)>1 1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断 select * from people where peopleId in (select peopleId from people group by peopleId having cou...

试试下面的语句: delete 表 where (select count(1) from 表 as a where a.filename=表.filename and a.filetime>=表.filetime)>3

--你分组一下就可以得到重复的数据了 SELECT Lname,UserName,count(id) as '在表中重复出现的次数' where LinkUser GROUP BY Lname,UserName HAVING count(id)>1 /* SELECT * FROM LinkUser WHERE ISNULL(Lname,'')=ISNULL(UserName,'') */

(select min(rowid) from vitae group by peopleId,seq having count(*)>1)...在A表中存在一个字段“name”,而且不同记录之间的“name”值有可能会相同,...

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