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一张数据表,存在重复数据.sElECt ID,NAmE,COUNT(...

select ID, count(Name) from A group by ID having count(Name) > 1

select name,count(1)from tabnamegroup by namehaving count(1) > 1

select id, name, memo from A where id in (select id from A group by id having count(1) >= 2)

select id from 表名 group by id having count(id) >1

select a,count(*) from table group by a having count(*)>1 嗯。是的。这样是查出来该字段重复2次以上的列。

select * from (select 姓名,身份证,家庭住址,银行帐号,备注,row_number() over (partition by 姓名,身份证 order by numrow desc) ssfrom (select 姓名,身份证,家庭住址,银行帐号,备注,row_number() over (partition by 姓名,身份证 order by ...

select 姓名列,count(1) as [重复次数] from 表名 group by 姓名列 having count(1)>=2 order by 重复次数 desc

查看可用如下方法: 1、创建测试表,插入数据: create table product(id int,name varchar(10),totol int)insert into product values (1,'香蕉',100)insert into product values (2,'橘子',67)insert into product values (3,'葡萄',89)insert...

友善的提醒两点,如有帮助还望采纳,谢谢! 第一、你这个语句本身写的有点麻烦,简化如下 SELECT [Store_Abbreviation] ,[Goodname], [Goodmodel] ,SUM(Order_Quantity) AS Order_Quantity, [Workid]from [fangtaidata].[dbo].[SalesStatistics]...

select ID,count(ID) from tablename group by ID having (count(ID)>1)

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