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sql多列多条件

select sum(case when con1||con2='11' then count else 0 end) 三星笔记本, sum(case when con1||con2='12' then count else 0 end) 三星台式机, sum(case when con1||con2='22' then count else 0 end) 苹果笔记本, sum(case when con1||con2=...

select top 1 * from table where 许用合力 > 75 and 许用扭矩 > 10 and 传动滚筒直径 = 1000 order by 许用扭矩, 许用合力 --输出结果就是先符合条件数据,再按许用扭矩和许用合力的升序排列,然后选取第一条,即最近的一条数据。

这个sql可以通过将初始查询结果集用括号括起来当作一个子查询(也可以称之为虚拟表),然后再对其实施进一步筛选从而获得另一个结果集的办法予以实现。 例如列出各科平均分在80到90分的同学姓名和各科平均分 select stu.name,t.平均分 from stu, (...

SQL = "select * from 档案 where 1 = 1 "If Combo1.Text "全部" Then SQL = SQL & " and " & "姓名='" & Combo1.Text & "'"End ifIf Combo2.Text "全部" Then SQL = SQL & " and " & "年龄='" & Combo2.Text & "'"End ifIf Combo3.Text "全部" ...

修改前:1列多行数据 修改后:合并成一列 示例语句 select类别, 名称 = ( stuff( (select ',' + 名称 from Table_A where 类别 = A.类别 for xml path('')), 1, 1, '' ) )from Table_A as A group by 类别

access和sql稍微有点区别,在一个楼主的统计函数用错了,应该是sum吧。 SELECT 型号, sum(IIf(是否报废='否',1,0)) AS 未报废数量, sum(IIf(是否借出='是',1,0)) AS 已借出数量 FROM a GROUP BY 型号;

以下语句完美解决! SELECT id FROM dollar WHERE id in(SELECT id FROM dollar WHERE type NOT IN('a') GROUP BY id HAVING SUM([money])>=300) AND id in(SELECT id FROM dollar WHERE type IN('c','d') GROUP BY id HAVING SUM([money])

select * from table where column_a in (select 条件N from table where XXX ) 总之你的多个“条件”如果能用select出来的话,把结果放到in里就可以了。

只能通过union all连接,如: select a from table where a like '' union alll select b from table where b like '' union alll select c from table where c like '' union alll select d from table where d like ''

SQL 代码如下所示: 1、 select max(case when F1%3=1 then F1 else 0 end) a, max(case when F1%3=2 then F1 else 0 end) b, max(case when F1%3=0 then F1 else 0 end) c from HLR151 group by (F1-1)/3 效果: 2、 select c1=a.F1,c2=b.F1,c3...

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